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x111+x41/2dx is equal to 

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a
12t55+2t33+t+c, where t=1+1x4
b
-12t55-2t33+t+c, where t=1+1x4
c
t55-2t33+t+c, where t=1+1x4
d
None of these

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detailed solution

Correct option is B

Let I=∫dxx111+x41/2=∫dxx11⋅x21+1/x41/2Let 1+1x4=t2 .  Then −4x5dx=2tdt⇒ I=∫dxx131+1/x41/2             =−14∫2tdtx8t             =−12∫t2−12dt            =−12∫t4−2t2+1dt           =−12t55−2t33+t+c, where t=1+1x4


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