∫x+x2+1dx equals ( where C is integration Constant) to

Let I=∫x+x2+1dx Let x+x2+1=t….(1) Rationalize ⇒x2+1−x=1t….(2) Subtract (1) &(2)⇒2x=t−1t⇒x=12t−1tDifferentiating with respect to  x on both sidesdx=121+1t2dt∴I=12∫t12+t−32dt=13t32−t−12+C   , where t= x+x2+1