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$\int \frac{1}{x + x^{5}} d x = f (x) + c, t h e n t h e v a l u e o f \int \frac{x^{4}}{x + x^{5}} d x =$

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logx-f(x)+c

f(x)+logx+c

f(x)-logx+c

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Correct option is A

∫x4x+x5dx add & subtract 1 in the numerator= ∫x4+1x+x5dx− ∫1x+x5dx =∫1+x4x1+x4dx−∫1x+x5dx=∫1xdx−∫1x+x5dx =logx−fx+c given ∫1x+x5dx=fx

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∫1x+x5dx=f(x)+c, then the value of ∫x4x+x5dx=

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$\int \frac{1}{x + x^{5}} d x = f (x) + c, t h e n t h e v a l u e o f \int \frac{x^{4}}{x + x^{5}} d x =$