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$\int \frac{8 x + 13}{\sqrt{4 x + 7}} d x = = A (4 x + 7)^{3 / 2} + B (4 x + 7)^{1 / 2} + C t h e n A + B =$

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Correct option is B

∫8x+134x+7dx=∫8x+14−14x+7dx=∫2(4x+7)−14x+7dx=2∫4x+7dx−∫14x+7dx=2(4x+7)3/24×32−(4x+7)1/24×12+C=13(4x+7)3/2−12(4x+7)1/2+C

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∫8x+134x+7dx ==A(4x+7)3/2+B(4x+7)1/2+C then A+B=

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$\int \frac{8 x + 13}{\sqrt{4 x + 7}} d x = = A (4 x + 7)^{3 / 2} + B (4 x + 7)^{1 / 2} + C t h e n A + B =$