∫x51+x32/3dx=A1+x38/3+B1+x35/3+c , then
A=14,B=15
A=18,B=-15
A=-18,B=15
None of these
Let 1+x3=t2 ⇒ 3x2dx=2tdt∴ ∫x51+x32/3dx=∫x31+x32/3x2dx =∫t2−1t22/3x2dx =23∫t2−1t7/3dt =23∫t13/3−t7/3dt =23316t163−310t10/3+c =181+x38/3−151+x35/3+c