First slide
Methods of integration
Question

  2x12+5x9dx1+x3+x53=

Moderate
Solution

I=  2x12+5x91+x3+x53dx=  5x6+2x3dx1+x2+x53

 Putting 1+x-2+x-5=t , then 

      2x35x6dx=dt

           I=  dtt3=12t2=121+x2+x52

        =x102x5+x3+12+c

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