∫$$1x$$−xdx is equal to

Correct option is 32log⁡|x−1|+C

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$\int \frac{1}{x - \sqrt{x}} dx$ is equal to

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2log⁡|x+1|+C

log⁡|x+1|+C

2log⁡|x−1|+C

2log⁡|x+1|+C

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detailed solution

Correct option is C

∫1x−xdx=∫1x(x−1)dx Let x−1=t⇒12x=dtdx⇒dx=2xdt∴1x(x−1)dx=∫1xt2xdt=∫2tdt=2⋅log⁡|t|+C =2log⁡|x−1|+C

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∫1x−xdx is equal to

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$\int \frac{1}{x - \sqrt{x}} dx$ is equal to