∫x1−x3dx is equal to
23sin−1x23+C
32sin−1x3/2+C
32sin−1x23+C
23sin−1x3/2+C
I=∫x1−x3dx=∫x1−x3dx=∫x1−x3/22dx
put x3/2=t⇒xdx=23dt
so, I=23∫dt1−t2=23sin−1x3/2+C