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 x3(x1)3exdx is equal to 

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a
ex(x−1)+c
b
−ex(x−1)2+C
c
2ex(1−x)2+C
d
ex(x−1)2+C

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detailed solution

Correct option is D

Let I=∫x−3(x−1)3exdx=∫x−1−2(x−1)3exdx=∫exx−1(x−1)3−2(x−1)3dx=∫ex1(x−1)2−2(x−1)3dxLet f(x)=1(x−1)2⇒f′(x)=−2(x−1)3 ∴ I=ex(x−1)2+C ∵∫exf(x)+f′(x)dx=exf(x)


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