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Q.

∫1+x−x−1ex+x−1dx is equal to

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a

(x+1)ex+x−1+C

b

(x−1)ex+x−1+C

c

−xex+x−1+C

d

xex+x−1+C

answer is D.

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Detailed Solution

∫1+x−x−1ex+x−1dx =∫xex+x−11−1x2+ex+x−1dx =xex+x−1−∫ex+x−1dx+∫ex+x−1dx =xex+x−1+C
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