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Q.

∫(1+x−x−1) ex+x−1dx =

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a

(x+1)ex+x−1+c

b

(x−1)ex+x−1+c

c

12xex+x−1+c

d

x.ex+x-1+c

answer is D.

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Detailed Solution

∫ex+x−1(1+x−x−1)dx               =∫[x[1−1x2]+1]ex+x−1dx    since ∫efxf'xgx+g'xdx=efxgx                =xex+x−1+c
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∫(1+x−x−1) ex+x−1dx =