∫$$x2x6+1$$ is equal to

Correct option is 413x32x6+1+12logx3+x6+1+C

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$\int x^{2} \sqrt{x^{6} + 1} is equal to$

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13x33x6+1+12logx3+x6+1+C

13x32x6+1−12logx3+x6+1+C

13x32x6+1+12logx+x+1+C

13x32x6+1+12logx3+x6+1+C

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detailed solution

Correct option is D

Let I=∫x2x6+1dx=∫x2x32+1 dx Put x3=tx2dx=dt3I=13∫t2+1dxI=13t2t2+1+12log⁡t+t2+1+C=13x32x6+1+12log⁡x3+x6+1+C

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∫x2x6+1 is equal to

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$\int x^{2} \sqrt{x^{6} + 1} is equal to$