First slide
Evaluation of definite integrals
Question

1+2x+3x2+4x3+dx where 0<|x|<1

Moderate
Solution

let

S=1+2x+3x2+4x3+xS= x+2x2+3x3+(1x)S=1+x+x2+x3+(1x)S=11xS=1(1x)2S=(1x)21+2x+3x2+dx=(1x)2dx=(1x)1(1)(1)+c=(1x)1+c

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