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$\int \frac{x^{3} - 1}{4 x^{3} - x} d x$ is equal to

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14x+log⁡|x|−316log⁡|2x−1|−916log⁡|2x+1|+C

14x−log⁡|x|−516log⁡|2x−1|−716log⁡|2x+1|+C

14x−log⁡|x|−716log⁡|2x−1|+916log⁡|2x+1|+C

14x+log⁡|x|−716log⁡|2x−1|−916log⁡|2x+1|+C

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detailed solution

Correct option is D

x3−14x3−x=14+14x−1x(2x−1)(2x+1)=14+1x−7812x−1−9812x+1∫x3−14x3−xdx=14x+log⁡|x|−716log⁡|2x−1|−916log⁡|2x+1|+C

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∫x3−14x3−xdx is equal to

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$\int \frac{x^{3} - 1}{4 x^{3} - x} d x$ is equal to