∫x3−1x4+1(x+1)dx=
14ln1+x4+13ln1+x3+c
14ln1+x4−13ln1+x3+c
14ln1+x4−ln(1+x)+c
14ln1+x4+ln(1+x)+c
∫x3−1x4+1(x+1)dx=∫x4+x3−x4+1x4+1(x+1)dx=∫x3x4+1dx−∫1x+1dx=14lnx4+1−ln(x+1)+c