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x31x4+1(x+1)dx=

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a
14ln⁡1+x4+13ln⁡1+x3+c
b
14ln⁡1+x4−13ln⁡1+x3+c
c
14ln⁡1+x4−ln⁡(1+x)+c
d
14ln⁡1+x4+ln⁡(1+x)+c

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detailed solution

Correct option is C

∫x3−1x4+1(x+1)dx=∫x4+x3−x4+1x4+1(x+1)dx=∫x3x4+1dx−∫1x+1dx=14ln⁡x4+1−ln⁡(x+1)+c


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