∫01x4(1−x)41+x2dx=
0
π−227
227−π
π+227
I=∫01x8−4x7+6x6−4x5+x41+x2dx
=∫10(x6−4x5+5x4−4x2+4−41+x2)dx
=17−23+1−43+4−π=227−π