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$\int_{3}^{6} \frac{\sqrt{x}}{\sqrt{9 - x} + \sqrt{x}} d x =$

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detailed solution

Correct option is D

I=∫36 x9−x+xdx----1I=∫36 9−xx+9−xdx----2(1)+(2)⇒2I=∫36 dx=(x)36=6−3=3⇒I=32

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∫36x9−x+xdx=

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$\int_{3}^{6} \frac{\sqrt{x}}{\sqrt{9 - x} + \sqrt{x}} d x =$