∫555x.55x.5x dx=
55x(log5)3+c
5x(log5)3+c
555x(log5)3+c
555x=t
555xlog5.55xlog5.5x.log5 dx= dt
∫555x.55x.5x dx= ∫1(log5)3dt=1(log5)3t+C
=555x(log5)3+C