First slide
Evaluation of definite integrals
Question

0x(1+x)(1+x2)dx=

Easy
Solution

0π/2Tanθ1+Tanθdθ           x=tanθdx=sec2θ

I=0π/2SinθSinθ+Cosθdθ

I=0π/2CosθCosθ+Sinθdθ

I=0π/2dθ=π2

I=π4

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