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a
(1+x)−1+c
b
(1−x)−1+c
c
(1−x)−1−1+c
d
None of these
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Correct option is B
∫1+2x+3x2+4x3+⋯dx=∫(1−x)−2dx=(1−x)−1+cSimilar Questions
If then the value of
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