∫x3−1x3+xdx is equal to
x−loge|x|+logex2+1−tan−1x+C
x−loge|x|+12logex2+1−tan−1x+C
x+loge|x|+12logex2+1+tan−1x+C
none of these
∫x3−1x3+xdx=∫1−11+x2−1x+xx2+1dx=x−tan−1x−loge|x|+12logex2+1+C