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$\int \frac{x^{3} - 1}{x^{3} + x} d x is equal to$

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x−loge⁡|x|+loge⁡x2+1−tan−1⁡x+C

x−loge⁡|x|+12loge⁡x2+1−tan−1⁡x+C

x+loge⁡|x|+12loge⁡x2+1+tan−1⁡x+C

none of these

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detailed solution

Correct option is B

∫x3−1x3+xdx=∫1−11+x2−1x+xx2+1dx=x−tan−1⁡x−loge⁡|x|+12loge⁡x2+1+C

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∫x3−1x3+xdx is equal to

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$\int \frac{x^{3} - 1}{x^{3} + x} d x is equal to$