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x3x1+x6dx is equal to 

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a
16log⁡x4−x2+11+x22+C
b
16tan−1⁡x2+122+C
c
log⁡x4−x2+11+x22+C
d
tan−1⁡x2+122+C

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detailed solution

Correct option is A

I=12∫t−11+t3dt where t=x2=12∫−23(1+t)+13(2t−1)t2−t+1dt (After partial fractions) =16⋅ln⁡x4−x2+1x2+12+C


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ex1+ex2+exdx is equal to 


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