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x4x1/4x5dx is equal to 

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a
4151−1x35/4+C
b
451−1x35/4+C
c
4151+1x35/4+C
d
None of these

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detailed solution

Correct option is A

∫x4−x1/4x5dx=∫1x41−1x31/4dx Putting 1−1x3=t, we get I=13∫t1/4dt=415t5/4+C=4151−1x35/4+C


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