∫xx9+1x2+1dx=f(x) and f(0)=0 find the value of f(1)
119315−π4+12log2
119315−π4+log2
283315−π4+log2
263315−π4+12log2
∫xx9+1x2+1dx=∫x8−x6+x4−x2+1+x−11+x2dx
f(x)=x99−x77+x55−x33+x+12log1+x2−tan−1x+Cf(0)=0⇒C=0∴f(1)=263315−π4+12log2