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27xx+9xdx is equal to

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a
1/2
b
3/2
c
5/2
d
0

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detailed solution

Correct option is C

∫27 xdxx+9−x---iI=∫27 9−x9−x+9−(9−x)dxI=∫27 9−x9−x+xdx----iiOn adding Eqs. (i) and (ii), we get2I=∫27 xx+9−x+9−xx+9−xdx=∫27 dx=|x|27=5so,  I=52


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