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Introduction to integration
Question
∫
(
1
+
4
x
+
6
x
2
+
4
x
3
+
x
4
)
d
x
=
Easy
A
4
+
12
x
+
12
x
2
+
4
x
3
+
C
B
(
1
+
x
)
5
5
+
C
C
(
1
+
x
)
6
5
+
C
D
(
1
+
x
)
3
3
+
C
Solution
∫
(
1
+
x
)
4
d
x
=
(
1
+
x
)
5
5
+
C
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