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Q.

∫x6+x4+x22x4+3x2+6dx

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a

1182x6+3x4+6x23/2+C

b

1122x6+3x4+6x23/2+C

c

1182x6+3x4+6x22/3+C

d

1122x6+3x4+6x22/3+C

answer is A.

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Detailed Solution

I=∫x6+x4+x22x4+3x2+6=∫x5+x3+x2x6+3x4+6x2dx Let 2x6+3x4+6x2=t2∴12x5+x3+xdx=2tdt∴I=112∫2t2dt=1182x6+3x4+6x23/2+c
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