First slide
Methods of integration
Question

3x2+2xx6+2x5+x4+2x3+2x2+5dx=

Moderate
Solution

3x2+2x(x3+x2+1)2+22dx

Let x3+x2+1=t

dtt2+22=12tan1(t2)+c

=12tan1[x3+x2+12]+c

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