First slide
Methods of integration
Question

xcosx+12x3esinx+x2dx

Moderate
Solution

I=(xcosx+1)esinxdxesinxx2xesinx+1

 Put 2xesinx+1=t2

 2esinx+esinxcosxxdx=2tdt esinx(1+xcosx)dx=tdt I=tdtt212t I=2dtt21=logt1t+1+C,

where t2=2xesinx+1

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