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xcosx+12x3esinx+x2dx

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a
log ⁡2xesin⁡x+1−12xesin⁡x+1+1+C
b
log ⁡2xesin⁡x−1+12xesin⁡x+1+1+C
c
log⁡2xesin⁡x+1+12xesin⁡x−1+1+C
d
log⁡2xesin⁡x+1+12xesin⁡x−1−1+C

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detailed solution

Correct option is A

I=∫(xcos⁡x+1)esin⁡xdxesin⁡xx2xesin⁡x+1 Put 2xesin⁡x+1=t2⇒ 2esin⁡x+esin⁡xcos⁡xxdx=2tdt⇒ esin⁡x(1+xcos⁡x)dx=tdt∴ I=∫tdtt2−12⋅t I=2∫dtt2−1=log⁡t−1t+1+C,where t2=2xesin⁡x+1


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