Q.
In ΔABC, the coordinates of the vertex A are 4,−1, and lines x−y−1=0 and 2x−y=3 are the internal bisectors of angles B and C. Then, the radius of the in circle of triangle ABC is
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a
4/5
b
3/5
c
6/5
d
7/5
answer is C.
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Detailed Solution
Incenre 1 is point of intersection of two angle bisectors which is ( 2,1).IA=22+22=22Also, AI=rcosecA2∠BIC=π2+A2or tanπ2+π2=1−21+2or tanA2=3So, r=AIcosecA2=221+1922×310=65
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