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In $ΔABC$ , if the orthocenter is (1,2) and the circumcenter is (0,0) then centroid of $ΔABC$ is

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(1/2,2/3)

(1/3,2/3)

(2/3,1)

None of these

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detailed solution

Correct option is B

G≡(1×1+2×03,2×1+2×03)≡(13,23)

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In ΔABC, if the orthocenter is (1,2) and the circumcenter is (0,0) then centroid of ΔABC is

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In $ΔABC$ , if the orthocenter is (1,2) and the circumcenter is (0,0) then centroid of $ΔABC$ is