In $\mathrm{\Delta ABC}$, the sides BC=5, CA=4 and AB=3. If $\mathrm{A}\equiv (0,0)$ and the internal bisector of angle A meets BC in $\mathrm{D}(\frac{12}{7},\frac{12}{7})$, then incentre of $\mathrm{\Delta ABC}$ is

• A

  (2,2)

• B

  (3,2)

• C

  (2,3)

• D

  (1,1)