ABC is a triangle and 'O', any point in the plane of the triangle. The lines AO,BO and CO meet the sides BC, CA and AB in D,E,F respectively. Then ODAD+OEBE+OFCF equal to
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a
1
b
−1
c
ODAD.OEBE.OFCF
d
0
answer is A.
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Detailed Solution
let O = G be the centroid of theΔleABC G divides AD in 2:1G divides BE in 2:1G divides CF in 2:1,ODAD+OEBE+OFCF =GDAD+GEBE+GFCF =13+13+13=1
ABC is a triangle and 'O', any point in the plane of the triangle. The lines AO,BO and CO meet the sides BC, CA and AB in D,E,F respectively. Then ODAD+OEBE+OFCF equal to