ABC is a triangular park with AB=AC=100m . A clock tower is situated at the midpoint  of BC . The angles of elevation of the top of the tower at A and B are cot−1⁡3.2,cosec−1⁡2.6 The height of tower is …mt

AB=AC=100m (correction)  Let DP= clock tower =hm∠PAD=α=cot−1⁡3.2⇒cot⁡α=3.2∠PBD=β=cosec−1⁡2.6⇒cos⁡ecβ=2.6cot⁡β=2.4 In △PAD and 9nΔPBDAD=hcot⁡α=3.2hBD=hcot⁡B=2.4h In △ABDAB2=AD2+BD21002=(3.2)2+(2.h)2h2=16h2∴h=25m