ABCD is a rectangle with A(−1,2),B(3,7) and AB:BC=4:3. If P is the centre of the rectangle, the the distance of P from each corner is equal to

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142

3414

2413

5418

answer is D.

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Detailed Solution

Since ABCD is a rectangle,(AC)2=(AB)2+(BC)2=(AB)2[1+916]=2516(AB)2and PA=AC2=5AB8=58(−1−3)2+(2−7)2=5418

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