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$ABCD$ is a square . $A \equiv (1, 2), B (3, - 4) .$ If line CD passes through $(3, 8)$ , then the midpoint of CD is

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2,6

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28/5, 1/5

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detailed solution

Correct option is D

mAB=−4−23−1=−3Thus, the equation of CD is y−8 =3x−3,i.e., y+3x=17.The equation of the right bisector of AB is y+1=13x−2or 3y=x−5Solving it with line CD, we get x=28/5, y=1/5. Thus the midpoint of CD is 28/5, 1/5

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ABCD is a square . A≡1,2,B3,−4. If line CD passes through (3,8), then the midpoint of CD is

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$ABCD$ is a square . $A \equiv (1, 2), B (3, - 4) .$ If line CD passes through $(3, 8)$ , then the midpoint of CD is