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Q.

ABCD is a square whose side is a. The equation of the circle circumscribing the square, taking AB and AD as axes of reference, is

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a

x2+y2+ax+ay=0

b

x2+y2+ax−ay=0

c

x2+y2−ax−ay=0

d

x2+y2−ax+ay=0

answer is C.

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Detailed Solution

The circle passes through (0, 0), (a, 0), (0, a) and  (a, a)Hence , the required equation is x2+y2−ax−ay=0
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