ABCD is a square whose vertices A (0,0) B (2,0), C (2,2), D (0, 2). This square is rotated in the xy-plane with an angle of 300 in anticlockwise direction about an axis passing through the vertex A, the equation of the diagonal BD of this rotated square is
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a
3x+(1−3)y=3
b
(1+3)x−(1−2)y=2
c
(2−3)x+y=2(3−1)
d
3x+(1−2)y=3−1
answer is C.
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Detailed Solution
New coordinates ofB=0+232,0+212=3,1C=0+2−12,0+232=−1,3New equation of BD is y−3=3−1−(3+1)(x+1)y−3=−(2−3)(x+1)=−(2−3)x−2+3i.e., (2−3)x+y=2(3−1)