Questions
In the above problem, coordinates of the point P such that |PA – PB| is minimum are
a
-920,-125
b
320,125
c
920,-125
d
-920,125
detailed solution
Correct option is A
The minimum value of |PA – PB| is zero which is attained if PA = PB, i.e., P must lie on the perpendicular bisector of AB.The equation of perpendicular bisector of AB isy=12=2(x-1) or y=2x-32Solving it with the given line, we get P≡-920,-125Talk to our academic expert!
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If the equation of the locus point equidistant from the points and is then the value of c is
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