Q.

In the above problem, coordinates of the point P such that |PA – PB| is minimum are

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a

-920,-125

b

320,125

c

920,-125

d

-920,125

answer is A.

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Detailed Solution

The minimum value of |PA – PB| is zero which is attained if PA = PB, i.e., P must lie on the perpendicular bisector of AB.The equation of perpendicular bisector of AB isy=12=2(x-1)   or    y=2x-32Solving it with the given line, we get P≡-920,-125
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In the above problem, coordinates of the point P such that |PA – PB| is minimum are