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The absolute value of 1019sinx1+x8dx is

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a
less than 10−7
b
more than 10−7
c
equal to 10−7
d
none of these

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detailed solution

Correct option is A

For x≥10, we have |sin⁡x|≤1 and 1+x8≥108⇒11+x8≤10−8Therefor1∫1019 sin⁡x1+x8dx∣≤∫1019 |sin⁡x|1+x8dx≤∫1019 10−8dx=910−8<10−7


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