The absolute value of slope of common tangents to parabola y2=8x and hyperbola 3x2−y2=3 is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
answer is 2.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Tangent to y2=8x⇒y=mx+2m → 1 since y=mx+am given hyperbola equation is x21-y23=1 Tangent to x21-y23=1 is y=mx±m2−3 →2 since y=mx±a2m2-b2 1, 2 represents same line . ⇒2m=m2-3⇒4 =m2m2-3⇒m=±2