The absolute value of slope of common tangents to parabola y2=8x and hyperbola 3x2−y2=3 is
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answer is 2.
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Detailed Solution
Tangent to y2=8x⇒y=mx+2m → 1 since y=mx+am given hyperbola equation is x21-y23=1 Tangent to x21-y23=1 is y=mx±m2−3 →2 since y=mx±a2m2-b2 1, 2 represents same line . ⇒2m=m2-3⇒4 =m2m2-3⇒m=±2