The acute angle between the lines y=2−3x−6  and y=2+3x+8 is

If   is acute angle between two lines  y=m1x−a and  y=2+3x+8 then  tanθ=m1−m21+m1m2Hence, tanθ=2−3−2+31+2−32+3=−231+4−3=3It gives θ=60°Therefore, the acute angle between the given lines is  θ=60°