For all complex numbers z1 and z2 satisfying |z1|=12 and |z2−3−4i|=5 the minimum value of |z1−z2| is equal to :

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answer is B.

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Detailed Solution

|z1|=12 ⇒|z1−0|=12 So, z2 lies on the circle with centre at (3,4) and radius 5.Minimum distance between z1 and z2 .PQ=OP−OQ=12−10=2

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