For all complex numbers z1  and  z2  satisfying |z1|=12  and  |z2−3−4i|=5  the minimum value of  |z1−z2|  is equal to :

|z1|=12 ⇒|z1−0|=12 So, z2  lies on the circle with centre at (3,4) and radius 5.Minimum distance between z1  and  z2 .PQ=OP−OQ=12−10=2