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For all $n \in N, n (n + 1) (2 n + 1)$ is divisible by

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Correct option is A

We have n(n+1)(2n+1)=612+22+…+n2,∴ n(n+1)(2n+1) is divisible by 6 for all n∈N.

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For all n∈N,n(n+1)(2n+1) is divisible by

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For all $n \in N, n (n + 1) (2 n + 1)$ is divisible by