The AM of n numbers of a series is x→. If the sum of first (n - 1) terms is k, then the nth number is

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x→-k

nx→-k

x→-nk

nx→-nk

answer is B.

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Detailed Solution

Let the n numbers be x1,x2,…,xn , thenx¯=1n∑i=1n xi⇒x¯=x1+x2+…+xn−1+xnn⇒x¯=k+xnn ∵x1+x2+…+xn−1=k∴xn=nx¯−k

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