Questions
The AM of the series 1, 2, 4, 8, 16, . . ., 2n is
a
2n−1n
b
2n+1−1n+1
c
2n+1n
d
2n−1n+1
detailed solution
Correct option is B
The required AM isX¯=1+2+22+23+⋯+2nn+1=2n+1−1(n+1)(2−1)=2n+1−1n+1Talk to our academic expert!
Similar Questions
. If the mean of the distribution is 2.6, then the value of y is
| Variate x | 1 | 2 | 3 | 4 | 5 |
| Frequency f of x | 4 | 5 | y | 1 | 2 |
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