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$The AM of the series 1, 2, 4, 8, 16, \dots, 2^{n} is$

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2n−1n

2n+1−1n+1

2n+1n

2n−1n+1

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detailed solution

Correct option is B

The required AM is X¯=1+2+22+23+⋯+2nn+1 =2n+1−1(n+1)(2−1)=2n+1−1n+1

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Variate x	1	2	3	4	5
Frequency f of x	4	5	y	1	2

The AM of the series 1,2,4,8,16,…,2n is

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$The AM of the series 1, 2, 4, 8, 16, \dots, 2^{n} is$