The angle between the diagonal of a quadrilateral formed by the lines xa+yb=1, xb+ya=1, xa+yb=2 and xa+ya=2 is
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a
π4
b
π2
c
π3
d
π6
answer is B.
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Detailed Solution
Clearly, distance between the parallel lines xa+yb=1 and xa+yb=2 is same as the distance between the parallel lines xa+yb=1 and xb+ya=2.Therefore, quadrilateral is rhombus.