The angle between the diagonals of the parallelogram formed by the points (1, 2, 3),(-1, -2, -1), (2, 3, 2), (4, 7, 6) is

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cos−1(7)

cos−17155

cos−17465

answer is C.

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Detailed Solution

D.r’s of AC = (1,1,-1), D.r’s of BD = (5,9,7)cosθ=|5+9−7|3.155⇒θ=cos−17465

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