The angle between the line r¯=(5i¯−j¯−4k¯)+λ(2i¯−j¯+k¯) and the plane r¯.(3i¯−4j¯−k¯)+5=0 is
sin−15291
sin−19156
sin−15156
sin−1956
From the line (a1,b1,c1)=z,−1,1
From the plane (a2,b2,c2)=(3,−4,−1)
sinθ=|a1a2+b1b2+c1c2|a12+b12+c12a22+b22+c22